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3y^2-21y+13=0
a = 3; b = -21; c = +13;
Δ = b2-4ac
Δ = -212-4·3·13
Δ = 285
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{285}}{2*3}=\frac{21-\sqrt{285}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{285}}{2*3}=\frac{21+\sqrt{285}}{6} $
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